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- The sum of the ages of Kidambi and Srikanth 14 years hence will be equal to 2 times their present age. If at present Kidambi is 8 years elder to Srikanth, then what are their present ages?
A. 22, 8
B. 29, 12
C. 18, 10
D. 13, 6
E. None of these
Correct option is : C
Solution:
Let the present ages of Kidambi and Srikanth be x years and y years respectively.
As per the question,
(x + 14) + (y + 14) = 2(x + y)
x + y + 28 = 2x + 2y
x + y = 28 …..(i)
Also,
y + 8 = x
x – y = 8 …..(ii)
Solving eqns (i) and (ii), we get
x = 18 and y = 10
Therefore, Present ages of Kidambi and Srikanth is 18 years and 10 years respectively
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- 6 years ago, the ratio of the ages of Arun and Prathap is 7: 6. Present age of Rajeev is 10 years more than one – sixth of Prathap’s present age. Find the ratio of present age of Prathap and Rajeev, if Arun’s age after 6 years is 40 years?
A. 3: 2
B. 2: 1
C. 4: 5
D. 1: 3
E. None of these
Correct option is : B
Solution:
6 years ago, the ratio of the ages of Arun and Prathap = 7: 6 (7x, 6x)
Present ages of Arun and Prathap = 7x + 6, 6x + 6
Present age of Rajeev = (1/6)*Prathap’s present age + 10
Arun’s present age = 34 years
According to the question,
7x = 28
x = 4
Prathap’s present age = 6x + 6 = 30
Rajeev’s present age = (1/6)*30 + 10 = 15
Required ratio = 30: 15 = 2: 1
- The ratio of present ages of Sri and Gowtham is 3: 4. Mahesh is 6 years older than Sri and two years younger than Gowtham. Find the sum of the present ages of Sri and Mahesh?
A. 48 years
B. 50 years
C. 52 years
D. 54 years
E. None of these
Correct option is : D
Solution:
Ratio of present ages of Sri and Gowtham = 3: 4 (3x, 4x)
Mahesh = Sri + 6 = 3x + 6
Mahesh = Gowtham – 2 = 4x – 2
According to the question,
3x + 6 = 4x – 2
4x – 3x = 8
X = 8
Present age of Sri = 3x = 24 years
Present age of Mahesh = 24 + 6 = 30 years
Required sum = 24 + 30 = 54 years
- The product of the ages of Asha and Nithi is 540. If twice the age of Asha is more than Nithi’s age by 6 years, then find Asha’s age?
A. 18 years
B. 20 years
C. 16 years
D. 22 years
E. None of these
Correct option is : A
Solution:
Let the age of Asha and Nithi be x and y respectively,
x*y = 540
2*x = y + 6
X = (y + 6)/2
[(y + 6)/2]*y = 540
Y2 + 6y = 1080
Y2 + 6y – 1080 = 0
(y – 30) (y + 36) = 0
Y = 30, -36 (-36 will be eliminated)
Asha’s age = 540/30 = 18 years
- Naveena’s present age is four times her son’s present age and two fifth of her father’s present age. The average present age of all of them is 40 years. Find the sum of Naveena’s son’s present age and Naveena’s father’s present age?
A. 92 years
B. 74 years
C. 88 years
D. 86 years
E. None of these
Correct option is : C
Solution:
The ratio of present age of Naveena and her son’s age = 4 : 1 (4x, x)
Naveena’s present age = (2/5)*Naveena’s father’s present age
Naveena’s father’s present age = 10x
According to the question,
x + 4x + 10x = 120
15x = 120
x = 120/15
x = 8
Naveena’s father’s present age = 10x = 80 years
Naveena’s son’s present age = x = 8 years
Required sum = 80 + 8 = 88 years
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- The ratio of B’s age six years hence to C’s present age is 5: 3. B is eleven years younger than A. If A’s present age is twice the age of C, then find B’s age, 4 years ago?
A. 13 years
B. 15 years
C. 17 years
D. 16 years
C. None of these
Correct option is : B
Solution:
The ratio of B’s age six years hence to C’s present age = 5 : 3 (5x, 3x)
Present ages of B to C = 5x – 6 : 3x
Present ages of A to C = 2 : 1 (2x, x)
Present ages of A, B and C = 6x, 5x – 6, 3x
B = A – 11
A – B = 11
6x – (5x – 6) = 11
6x – 5x + 6 = 11
X = 5
B’s age, 4 years ago = 5x – 6 – 4 = 25 – 10 = 15 years
- After 2 years, the age of Karthi is 2 times the present age of Silambu. Preethi is 8 years elder than Silambu. Find the present age of Karthi, if the present age of Preethi is 23 years?
A. 28 years
B. 26 years
C. 24 years
D. 30 years
E. None of these
Correct option is : A
Solution:
The ratio of age of Karthi’s age after 2 years and Silambu’s present age
= 2 : 1 (2x, x)
Preethi’s present age = 23 years
Silambu’s present age = 23 – 8 = 15
Silambu’s present age = 15
X = 15
2x = 30
After 2 years, the age of Karthi = 30 years
Present age of Karthi = 28 years
- 4 years ago, the age of A is 2 times the present age of B. C is 12 years elder than B and 10 years younger than A. Find the present age of D, if the present age of C is 6 times the present age of D?
A. 3 years
B. 6 years
C. 7 years
D. 5 years
E. None of these
Correct option is : D
Solution:
The ratio of age of A, 4 years ago and the present age of B = 2: 1 (2x, x)
C = B + 12
C = A – 10
A – 10 = B + 12
2x + 4 – 10 = x + 12
X = 18
Present age of A = 2x + 4 = 40 years
Present age of B = 18 years
Present age of C = 18 + 12 = 30 years
Present age of C = 6* Present age of D
Present age of D = 30/6 = 5 years
- The ratio of present age of Ramesh and Karthi is 2: 3. Sheela is 3 years elder than Karthi. The average present ages of three of them is 25 years. Find the age of Janvi, 4 years ago, if the present age of Janvi is 2 times the present age of Ramesh?
A. 29 years
B. 35 years
C. 32 years
D. 27 years
E. None of these
correct option is : C
Solution:
The ratio of present age of Ramesh and Karthi = 2 : 3 (2x, 3x)
Sheela = 3 + Karthi = 3x + 3
Sum of the present ages of three of them = 75 years
2x + 3x + 3x + 3 = 75
8x = 72
x = 9
Present age of Ramesh = 2x = 18 years
Present age of Janvi = 2*Ramesh = 2*18 = 36 years
The age of Janvi, 4 years ago = 32 years
- The ratio between Gautham and Manoj is 35: x. Manoj is 6 years younger than Nisha. Nisha’s age after 8 years will be 30 years. The Gautham’s present age is 3 years less than the sum of the present age of Manoj and Nisha. Find the value of x?
A. 22
B. 16
C. 18
D. 17
E. None of these
Correct option is : B
Solution:
The present age of Gautham and Manoj = 35: x
Manoj = Nisha – 6
Nisha’s age = 30 – 8 = 22 years
Manoj = 22 – 6 = 16
Gautham’s age = (Manoj’s age + Nisha’s age) – 3
Gautham’s age = 16 + 22 – 3 = 35
The value of x = 16