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__Download Reasoning Questions with Answers Pdf__

**A borrows Rs. 800 at the rate of 12% per annum simple interest and B borrows Rs. 910 at the rate of 10% per annum, simple interest. In how many years will their amounts of debt be equal?**

A. 18

B. 20

C. 22

D. 24

E. 28

**Correct option is : C **

Let the period of time be T years

800 + 800 ×12 ×𝑇 = 910 + 910 ×10 ×𝑇

100 100

=> 800 + 96T = 910T + 91T

=> 96T – 91T = 910 – 800

=> 5T = 110

=> T = ^{110} = 22 years

5

**A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:**

A. 650

B. 690

C. 698

D. 700

E. None of these

**Correct option is : C **

S.I. for 1 year = Rs. (854 – 815) = Rs. 39.

S.I. for 3 years = Rs.(39 x 3) = Rs. 117. Principal = Rs. (815 – 117) = Rs. 698.

**3. A sum fetched a total simple interest of Rs. 4016.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum?**

A. Rs. 4462.50

B. Rs. 8032.50

C. Rs. 8900

D. Rs. 8925

E. None of these

**Correct option is : D**

**Solution:**

Principal = Rs. (100×4016.25)

9×5

= Rs. (401625)

45

= Rs. 8925

**1. A man lent Rs. 4500 at 30% compound interest per annum for 3 years. What is the difference between the interest earned by the man in the 2**^{nd}** year only and the interest earned by the man in the 3**^{rd}** year only?**

A. Rs. 545.5

B. Rs. 502

C. Rs. 526.5

D. Rs. 532

E. Rs. 529

**Correct option is : C **

**2. A man saves Rs.20,000 at the beginning of each year and puts the money in a bank that pays 10% interest per year, interest being compounded annually. What would be the total savings of the man at the end of 6 years?**

A. Rs. 196840

B. Rs. 169840

C. Rs. 189480

D. Rs. 199480

E. Rs. 168840

**Correct option is : B**

**Solution:**

The first Rs. 20000 would become 20000(1.1)^{6} after 6 years, the second will become 20000(1.1)^{5}.the third will become 20000 (1.1)^{4}, the fourth will become 20000 (1.1)^{3} , the fifth will become 20000(1.1)^{2} and the sixth will become 20000 (1.1).

Total amount = 20000 [(1.1) + (1.1)^{2} + (1.1)^{3} + (1.1)^{4} + (1.1)^{5} + (1.1)^{6}]

= (20000) (1.1) [ 1 + (1.1) + (1.1)^{2} + (1.1)^{3} + (1.1)^{4} + (1.1)^{5}]

= 22000 | (1.1)^{6} – 1 | = 22000 (7.72) = Rs. 169840 |

**3. Shyam deposited Rs. 80000 in a bank which pays 10% compound interest for 2 years. Then after 2 years, he started a business with amount (sum + interest) along with Ram, with capital of Rs. 60,000. Shyam invested for 6 months and left. Ram invested for the whole year. What will be the ratio of their profits at the end of the year?**

A. 150 : 221

B. 121 : 150

C. 121 : 130

D. 130 : 121

E. 155 : 101

**Correct option is : B**

**Solution:**

Capital of Shyam = Rs. 80,000 Rate of Interest = 10%

Time for which he deposited in bank = 2 years Amount = 80000 (1 + 10 )2

100

Amount = | 80000 × 121 | = Rs. 96800 |

100 |

Investment of Shyam in business = Rs. 96800 Investment of Ram in business = Rs. 60000

Ratio of their profits = | 96800 × 6 |

60000 × 12 |

Ratio = 968 : 1200 = 121 : 150

**Find the difference between simple and compound interest on Rs. 6000 for 1 year at 20% per but interest is calculated on half yearly**

A. 120

B. 60

C. 180

D. 72

E. 108

**Correct option is : B **

**2. Rs. X is required to earn a monthly interest of Rs. 400 at 10% per annum at simple interest. Rs. Y is required to earn same interest as X when compounded semi-annually at 10% pa. Find the difference between X and Y. A. 1170.74**

A. 1331.26

B. 928.34

C. 979.66

D. None of these

**Correct option is : A **

Total Interest =12 × 400 = 4800

P = | (S.I × 100) | × T = 48000 |

Compound interest = Y(1 + R )2

100– Y = 4800

Y = 46829.26

Difference = Rs. (48000 – 46829.26) =1170.74

**3. A invested some money at r% which grows to 676/441 times when invested for two years in a scheme where interest is compounded annually, how long will the same sum of money take to triple itself if invested at ‘r/100’% rate of interest in a scheme where the interest is computed using the simple interest method.**

A. 120 years

B. 840 years

C. 105 years

D. 720 years

E. None of these

**Correct option is : B**